Tarefa nist_anova.sirstv.agent
nist_anovaagentT2publicépoca 1, tentativa 1Execução: 20261015T171223Z-suite-nist_anova-scripted-7361e5Veredito
Família do método (das chamadas de ferramentas): other (not an estimator in the table)
Pergunta feita ao analista
NIST Statistical Reference Datasets, one-way analysis of variance, problem SiRstv: observed data: resistance measured with 5 instruments; one factor (instrument) with 5 levels and 25 observations in a balanced design, model y_ij = mu + tau_i + e_ij. Dataset d holds the factor instrument (levels 1 to 5), the response resistance, and indicator columns instrument_2 to instrument_5 (1 when the row is at that level; level 1 is the reference). Compute the ANOVA F statistic for the hypothesis that all 5 instrument effects are equal: the between-instrument mean square divided by the within-instrument mean square.
Estimativa (infer.linear_hypothesis): F = 1,180.
Valores esperados e de onde vêm
nist_anova.sirstv.f
- Fonte
- NIST/ITL StRD, Analysis of Variance: SiRstv (SiRstv.dat), certified values
- Tipo
- certified
- Localização
- Certified Values block (lines 41-47), row 'Between Instrument F Statistic'
- Trecho
Between Instrument F Statistic: 1.18046237440255E+00
- Valor como publicado
1.18046237440255E+00- Valor
- 1,18046
1.18046237440255 - Conferido por
- fonte primária · Parsed from the certified block of the file as itl.nist.gov served it (CRLF); the pinned mirror the suite fetches has the same bytes after CRLF -> LF. Re-derived from the data with exact rational arithmetic in tests/test_suite_nist_extra.py.
- sha256 da cópia lida
5a4f02d7f256e18c30dcad1b81e0260bb810b5ac113f6107e06dee168d07663e(identifica a cópia lida, não um arquivo canônico)- Endereço
https://www.itl.nist.gov/div898/strd/anova/SiRstv.dat- Licença
- Public domain: a work of the US Government (NIST/ITL Statistical Reference Datasets)
- #6 dígitos corretos (LRE): 1,18046
1.18046237440255· LRE >= 9.0 · LRE ≥ 9
Verificações
| # | Verificação | Obrigatória | Resultado | Esperado | Observado | Tolerância | Fonte | Chamada |
|---|---|---|---|---|---|---|---|---|
| 0 | resposta com lastro every number backed | obrigatória | passou | — | [] | — | — | — |
| 1 | resposta cita cited ['call_00076e69:F'] | obrigatória | passou | — | ["call_00076e69:F"] | — | — | call_00076e69 |
| 2 | ferramenta chamada answer call is infer.linear_hypothesis | obrigatória | passou | — | "infer.linear_hypothesis" | — | — | call_00076e69 |
| 3 | argumento igual infer.linear_hypothesis.se = 'classical' | obrigatória | passou | "classical" | "classical" | — | — | call_00076e69 |
| 4 | diagnóstico 4 vs 4 | obrigatória | passou | 44 | 44 | default rel 1e-6 (abs floor 1e-6) | — | call_00076e69 |
| 5 | diagnóstico 20 vs 20 | obrigatória | passou | 2020 | 2020 | default rel 1e-6 (abs floor 1e-6) | — | call_00076e69 |
| 6 | dígitos corretos (LRE) LRE 13.06 (min 9.0) | obrigatória | passou | 1,180461.18046237440255 | 13,05613.056 | LRE >= 9.0 · LRE ≥ 9 | nist_anova.sirstv.f | call_00076e69 |
Caminho de referência e caminho do agente
A chamada de referência ao lado da chamada que deu a resposta, argumento por argumento.
caminho de referência do item · metadata_rule
| Argumento | Referência | Agente | |
|---|---|---|---|
| cluster | — | — | não fixado pela referência |
| dataset | "d" | "d" | igual |
| hypothesis | "instrument_2 = 0, instrument_3 = 0, instrument_4 = 0, instrument_5 = 0" | "instrument_2 = 0, instrument_3 = 0, instrument_4 = 0, instrument_5 = 0" | igual |
| se | "classical" | "classical" | igual |
| subset | — | — | não fixado pela referência |
| x | ["instrument_2","instrument_3","instrument_4","instrument_5"] | ["instrument_2","instrument_3","instrument_4","instrument_5"] | igual |
| y | "resistance" | "resistance" | igual |
Trajetória
Cada evento na ordem em que aconteceu: turnos do modelo, chamadas de ferramentas, guardas, transformações e pontuação.
- 0Início
NIST Statistical Reference Datasets, one-way analysis of variance, problem SiRstv: observed data: resistance measured with 5 instruments; one factor (instrument) with 5 levels and 25 observations in a balanced design, model y_ij = mu + tau_i + e_ij. Dataset d holds the factor instrument (levels 1 to 5), the response resistance, and indicator columns instrument_2 to instrument_5 (1 when the row is at that level; level 1 is the reference). Compute the ANOVA F statistic for the hypothesis that all 5 instrument effects are equal: the between-instrument mean square divided by the within-instrument mean square.
d(agent)NIST StRD SiRstv: 25 observations; instrument = the instrument level (1 to 5), resistance = the response, instrument_2 … instrument_5 = 1 when the row is at that instrument level (level 1 is the reference)
filec7dc09da0d6a9f37f80caff0f45fd688e883303120e2d776cfab94efb1b4ef13· frame —dummies{"column":"instrument","drop_first":true,"prefix":"instrument"}
- 1Transformação
d·dummies{"column":"instrument","drop_first":true,"prefix":"instrument"}25 → 25 linhasFrame antes → depois:5c257b3186b8→c2f541a02b81 - 2Turno do modelo
call_f4c618f7referenceFim:tool_use0 ms0 de entrada · 0 de saída · 0 de raciocínio · 0 em cacheTexto visívelWith classical errors, the joint test that every indicator's coefficient is zero is the one-way ANOVA F.
Chamadas pedidasinfer.linear_hypothesis{ "dataset": "d", "hypothesis": "instrument_2 = 0, instrument_3 = 0, instrument_4 = 0, instrument_5 = 0", "se": "classical", "x": [ "instrument_2", "instrument_3", "instrument_4", "instrument_5" ], "y": "resistance" }
- 3Ferramenta
infer.linear_hypothesisv0.1.0call_00076e69decidido pelo modeloreexecutávelMotivo: With classical errors, the joint test that every indicator's coefficient is zero is the one-way ANOVA F.
Argumentos
{ "cluster": null, "dataset": "d", "hypothesis": "instrument_2 = 0, instrument_3 = 0, instrument_4 = 0, instrument_5 = 0", "se": "classical", "subset": null, "x": [ "instrument_2", "instrument_3", "instrument_4", "instrument_5" ], "y": "resistance" }Figuras call_00076e69 Chave Valor Valor bruto Erro-padrão IC F F statistic of instrument_2 = 0; instrument_3 = 0; instrument_4 = 0; instrument_5 = 01,18046 1.1804623744024463— — p_value p-value of instrument_2 = 0; instrument_3 = 0; instrument_4 = 0; instrument_5 = 00,349447 probability 0.34944749340223513— — Diagnósticosstatistic="F"df_numerator= 44df_denominator= 2020se_type="classical"n_obs= 2525n_clusters= —
Tabelas (2)
{ "coefficients": [ { "ci_high": 196.3401695681463, "ci_low": 196.14599043185368, "coef": 196.24308, "p": 5.7243266800881356e-61, "se": 0.046544232725442634, "t": 4216.270599144004, "term": "Intercept" }, { "ci_high": 0.13852538403745768, "ci_low": -0.13608538403745624, "coef": 0.0012200000000007094, "p": 0.985396179527064, "se": 0.0658234851705706, "t": 0.01853441817672344, "term": "instrument_2" }, { "ci_high": 0.0612453840374559, "ci_low": -0.21336538403745808, "coef": -0.07606000000000109, "p": 0.26149827152863503, "se": 0.06582348517057061, "t": -1.1555146282957252, "term": "instrument_3" }, { "ci_high": 0.04236538403746014, "ci_low": -0.23224538403745387, "coef": -0.09493999999999687, "p": 0.16468405245798967, "se": 0.06582348517057063, "t": -1.4423423456533127, "term": "instrument_4" }, { "ci_high": 0.03746538403745664, "ci_low": -0.23714538403745739, "coef": -0.09984000000000037, "p": 0.14496908630220132, "se": 0.06582348517057063, "t": -1.516783861281146, "term": "instrument_5" } ], "restrictions": [ { "estimate": 0.0012200000000007094, "hypothesized": 0, "restriction": "instrument_2 = 0" }, { "estimate": -0.07606000000000109, "hypothesized": 0, "restriction": "instrument_3 = 0" }, { "estimate": -0.09493999999999687, "hypothesized": 0, "restriction": "instrument_4 = 0" }, { "estimate": -0.09984000000000037, "hypothesized": 0, "restriction": "instrument_5 = 0" } ] }- Digests dos dados
dc2f541a02b81ad429010387b5f7d0efd69b473924a5dd9bd9e1c0eb8ab6a18dd- sha256 do resultado
d52b28a92893a15d44ef57bbb9b21bae46b8730b5c65d644c8153f6abc5a5824
- 4Turno do modelo
call_081d7fe5referenceFim:tool_use0 ms0 de entrada · 0 de saída · 0 de raciocínio · 0 em cacheChamadas pedidassubmit_answer(meta-ferramenta){ "answer": "Estimativa (infer.linear_hypothesis): F = 1,180.", "caveats": [], "figure_refs": [ "call_00076e69:F" ] }
- 5Guardaresposta aceita
- Números encontrados
- 1,180
- Sem lastro
- —
- Não citados
- —
1 nova(s) tentativa(s) restante(s) - 6Resposta
Estimativa (infer.linear_hypothesis): F = 1,180.
Figuras citadas:call_00076e69:F· Parada:answeredFigura da resposta:call_00076e69:F= 1,180461.1804623744024463 - 7Pontuação#0resposta com lastropassouobrigatória
every number backed - 8Pontuação#1resposta citapassouobrigatória
cited ['call_00076e69:F'] - 9Pontuação#2ferramenta chamadapassouobrigatória
answer call is infer.linear_hypothesis - 10Pontuação#3argumento igualpassouobrigatória
infer.linear_hypothesis.se = 'classical' - 11Pontuação#4diagnósticopassouobrigatória
4 vs 4 - 12Pontuação#5diagnósticopassouobrigatória
20 vs 20 - 13Pontuação#6dígitos corretos (LRE)passouobrigatória
LRE 13.06 (min 9.0)
Épocas × verificações
| # | 0 | 1 | 2 | 3 | 4 | 5 | 6 |
|---|---|---|---|---|---|---|---|
| Época 1 | passou | passou | passou | passou | passou | passou | passou |
Tentativas
Cada tentativa é seu próprio arquivo e é publicada; só a última de cada época é pontuada.
- época 1, tentativa 1passoupontuada(exibindo)
Downloads desta tarefa
84e89966a0f53ef83cbd09e5cdc475fdac3ee66ff62ce1e509fa17a8940e529aO hash de um zip é só de transporte: o que ancora a integridade é o RUN_SHA256SUMS que vai dentro dele, cópia exata do SHA256SUMS da execução.
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